8x^2+4x=1.5

Solution for 8x^2+4x=1.5 equation:

8x^2+4x=1.5

We move all terms to the left:

8x^2+4x-(1.5)=0

We add all the numbers together, and all the variables

8x^2+4x-1.5=0

a = 8; b = 4; c = -1.5;
Δ = b2-4ac
Δ = 42-4·8·(-1.5)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*8}=\frac{-12}{16}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*8}=\frac{4}{16}
=1/4
$